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Using double integration find the area of the domain bounded by the following lines: y=3/2sqrt(x); Y=3/2x when x varies between the point of line intersection (find it) and x=9. Make a sketch and show the domain.
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something like this...|dw:1351299452867:dw|
y is bounded by what above and what below?
x= (4y^2)/9
sorry I dont see it
oh wait, I think I misinterpreted the Q they want the area from the line of intersection to x=9
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Why do you need to use double integration for this?
|dw:1351299779254:dw|drawing not to scale @Hero we don't, but they want us too. It winds up being the exact same.
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