I am unsure as to writing some of the functions on here. But here goes:
Simplify:
3√125(x-10)3 Both the 3's are supposed to be exponents.
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OpenStudy (anonymous):
You mean this?\[\Huge \sqrt[3]{125(x-10)^3}\]
OpenStudy (anonymous):
Yes!
OpenStudy (anonymous):
Note: 125 = 5³
OpenStudy (anonymous):
Break it into \[\Huge \sqrt[3]{125} \cdot \sqrt[3]{(x-10)^3}\]
OpenStudy (anonymous):
So when simplifying it would be ^3√5^3(x-10)^3
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OpenStudy (anonymous):
Ohhhh I see
OpenStudy (anonymous):
Yeah, and you can simplify it ever more.
OpenStudy (anonymous):
Is this clear?
OpenStudy (anonymous):
^3√5^3*^3√(x-10)^3 ????
OpenStudy (anonymous):
@Helenshouse It shows that you don't see clearly :)
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OpenStudy (anonymous):
How are you showing ^3 ? Is there a short key to write this?
OpenStudy (anonymous):
Sigh, no but I sure am trying!
OpenStudy (anonymous):
Let me show you an example. \[\Large \sqrt[5]{a^5} = a \text{ because } a^5 = a \cdot a \cdot a \cdot a \cdot a\]
Now, what is \[\huge \sqrt[3]{5^3}\] and \[\Large \sqrt[3]{(x-10)^3}\]
OpenStudy (anonymous):
The first is ^3√125 right?
OpenStudy (anonymous):
The second is ^3√(x-10)^3 I am unsure........
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OpenStudy (anonymous):
No, I mean simplify it.
OpenStudy (anonymous):
@Helenshouse Let me put this way, can you convert cube root into exponent?
OpenStudy (anonymous):
Do you know any exponent properties?
OpenStudy (anonymous):
^3√125*(x-10)^3
OpenStudy (anonymous):
No, don't combine them. It makes it worse. Here, let me show you.
√25 = √5² = 5, right? Do you know why?
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OpenStudy (anonymous):
I am looking in my notes.
OpenStudy (anonymous):
Yes 5*5=25
OpenStudy (anonymous):
√25 = √5² = 5
Similarly, ³√ 125 = ....?
OpenStudy (anonymous):
5^3
OpenStudy (anonymous):
I am so lost here
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OpenStudy (anonymous):
You missed my point, what we're looking for is ³√ 125 ( not 125)
OpenStudy (anonymous):
Ok
OpenStudy (anonymous):
Let try again filling the second line by following the first line:
√25 = √5² = 5
Similarly, ³√ 125 = .... = ...
OpenStudy (anonymous):
√5^3 = 5*5*5 I'm not sure
OpenStudy (anonymous):
Do you understand that √5² = (5²)^( 1/2) ?
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