How many solutions does the following equation have?
3x + 6 = 3(x + 2)
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OpenStudy (anonymous):
factor the 3 on the right side and solve for x
3x+6 = 3x +6
everything cancels out and your left with no solution
OpenStudy (anonymous):
. A. exactly 2 solutions
B. exactly 1 solution
C. infinitely many solutions
D. no solutions
Those are the choices
OpenStudy (anonymous):
infinitely many
OpenStudy (anonymous):
So, its no solution?
OpenStudy (anonymous):
you can plug in any number and the equation will equal
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OpenStudy (anonymous):
yea 3x - 3x = 0
so your left without a variable
therefore its no solution
OpenStudy (anonymous):
How many do you want?
OpenStudy (anonymous):
Im confused.. gettin' three different answers.
OpenStudy (anonymous):
What do you mean Cliffsedge?
OpenStudy (anonymous):
Plug in any number you want for x and see if it works.
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OpenStudy (anonymous):
Okay
OpenStudy (anonymous):
@Kashan and @jayz657 are both incorrect.
OpenStudy (anonymous):
@jayz657 and @Kashan thats not right. the equation has infinitely many solutions. you can plug in infinitely many numbers and always get 0=0, which is true
jimthompson5910 (jim_thompson5910):
It can't be "no solution". Here's a counter-example showing why
3x + 6 = 3(x + 2)
3*0 + 6 = 3(0 + 2) ... Plug in x = 0
0 + 6 = 3(2)
6 = 6 .. which is TRUE
So clearly x = 0 works and it is a solution
OpenStudy (anonymous):
Logic FTW.
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