How many solutions does the following equation have? 3x + 6 = 3(x + 2)
factor the 3 on the right side and solve for x 3x+6 = 3x +6 everything cancels out and your left with no solution
. A. exactly 2 solutions B. exactly 1 solution C. infinitely many solutions D. no solutions Those are the choices
infinitely many
So, its no solution?
you can plug in any number and the equation will equal
yea 3x - 3x = 0 so your left without a variable therefore its no solution
How many do you want?
Im confused.. gettin' three different answers.
What do you mean Cliffsedge?
Plug in any number you want for x and see if it works.
Okay
@Kashan and @jayz657 are both incorrect.
@jayz657 and @Kashan thats not right. the equation has infinitely many solutions. you can plug in infinitely many numbers and always get 0=0, which is true
It can't be "no solution". Here's a counter-example showing why 3x + 6 = 3(x + 2) 3*0 + 6 = 3(0 + 2) ... Plug in x = 0 0 + 6 = 3(2) 6 = 6 .. which is TRUE So clearly x = 0 works and it is a solution
Logic FTW.
Ohh, so it is infinity ∞ ?
X may be any real number as a solution.
Ok thanks guys.
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