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I'm having a hard time figuring out what to do with the -2, since the denominators are equivalent already. What is my next step? Thanks! 7 2-3x ---- -2 = ----- x+5 x+5
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Common denom. x+5 -> 2 ( x+5 )
\[\frac{ 7 }{ x+5} -2 = \frac{ 2-3x }{ x+5 }\] So your saying: \[(2)\frac{ 7 }{ x+5} = (2)\frac{ 2-3x }{ x+5 }\] \[\frac{ 14 }{ 2(x+5)} = \frac{ 4-6x }{ 2(x+5) }\]? if so, why 2 and not -2?
Which part you multiply 2 ( x +5) = ....?
-> 7 - 2x - 10 = 2 - 3x - 2x - 3 = 2 + 3x 3x - 2x = 2 + 3 x = 5
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