Question

A bag of pins has 4 black, 2 brown and 6 blue pins in it. If 3 pins are selected without replacement then determine the probability
of getting black, brown and blue in that order?

Answer 1

please help me i would really appreciate it :)

Answer 2

ok

Answer 3

the number of ways to select pins such that one with each color is=4C1*2C1*6C1

the number of ways to select three =12C3
the probability is 4C1*2C1*6C1/12C3

Answer 4

i don't have calculator so u might solve it

Answer 5

yourself

Answer 6

thank you for the help but i dont really understand what the C meas

Answer 7

combination=C there is a buton on ur calculator

Answer 8

ah ok thank you im not sure if i have that cuz i live in australia but im sure i will work it out once again thank you so much for helping

Answer 9

plz give me medel if i helped i really need a bit of those to show them to my girlfriend

Answer 10

ok sure thing how do that.. sorry new to this

Answer 11

let me tell u

Answer 12

o thanks

Answer 13

did i do it?

Answer 14

yes

Answer 15

oh cool

Answer 16

hmmmm... in sentences told, the color are black, brown and blue.
but ur question, the color are red, green and blue. not sincron :p

Answer 17

oh sorry i was just wanted to change the colours cuz i dont like red or green i know im weird

Answer 18

also what does sincron mean

Answer 19

nopes... nevermind :)
so, whats problem now

Answer 20

is even take pins one by one ?

Answer 21

if yes, it should be
P(1Black and 1brown and 1blue) = 4/12 * 2/11 * 6/10

Answer 22

ok thank you and yeah i meant yes does * mean times

Answer 23

it can be 48/1320 = 2/55

Answer 24

ok thank you so much :)

Answer 25

welcome