Divide 3x^3 + 3x^2 + 2x – 2 by x + 3 using long division.

3x^2 – 6x + 20
3x^2 + 12x – 16
3x^2 + 12x – 16, R 58
3x^2 – 6x + 20, R -62

Question

Divide 3x^3 + 3x^2 + 2x – 2 by x + 3 using long division. 

3x^2 – 6x + 20
3x^2 + 12x – 16
3x^2 + 12x – 16, R 58
3x^2 – 6x + 20, R -62

anonymous · Answer

like polynomial long division?

anonymous · Answer

i think so. lol this is all it said

anonymous · Answer

3x^2 - 6x + 20 R -62
x + 3 | 3x^3 + 3x^2 + 2x - 2      start with first term only. What times x equals 3x^3 ?
            3x^3 + 9x^2
                        -6x^2 + 2x -2
                        -6x^2 - 18x
                                     20x - 2
                                     20x + 60
                                              -62

anonymous · Answer

so , it would be the last one ? (:

anonymous · Answer

start with first term only. What times x equals 3x^3 ? Write that above, do the multiplication and put that below. Subtract and continue in with that pattern

anonymous · Answer

hm if i remember correctly you do it jthe same as long divison
 so id be 20x+60 and R
 of 62

anonymous · Answer

It matches my answer. But do you understand HOW I did it

anonymous · Answer

wait -62

anonymous · Answer

@Burns123 is incorrect. See my work above

anonymous · Answer

@Burns123 still incorrect. See my work above

anonymous · Answer

D