Question

find maximum and minimum values for the function g(x)=x^3-3x

Answer 1

@hartnn

Answer 2

what u got as first derivative ?

Answer 3

3x^2-3=0
x^2=1
x=1,-1

Answer 4

should i take second derivative?

Answer 5

correct.
here u can just put the values in g(x) and by inspection u can tell which is max

Answer 6

mathematically, u should take 2nd derivative...

Answer 7

max at x=-1 and minimum at x=1

Answer 8

bt then why we took second derivative in last qn?

Answer 9

because we can't find the max or min just by putting the points and inspection, can we ?

Answer 10

i see is my final answers ryt?

Answer 11

....

Answer 12

u dr??

Answer 13

sorry, got disconnected...yes, its correct

Answer 14

one last qn and i am done ,,well for this qn i think i gt crct anser bt i want t o knw if i need to take second derivative

"find maximum and minimum value of 3x^4-8x^3+12x^2-48x+25

Answer 15

,,,

Answer 16

yes, u need to..

Answer 17

are answers 0 and 2?

Answer 18

mim at x=2

Answer 19

max at x=0 min at x=2 ryt?

Answer 20

yes, both are correct..i had doubt with max at x=0

Answer 21

thanx a lot!!!! it really helped
cant tell u hw thankful i am !!

Answer 22

seeya gn8 sweeet drms