Question

the perimeter of a rectangle is 32 ft. the length is 4 ft. longer than its width. find the length and width

Answer 1

I have with 16 and 8 so far

Answer 2

You can answer this question by setting up a system of equations.

Answer 3

2x+2y then what

Answer 4

2x+2y=32

Answer 5

x=length
y=width

Answer 6

Lets call x your length and y your width. You know that x=y+4

Answer 7

16+4?

Answer 8

So far you have:

2x+2y=32
x=y+4

Answer 9

Use a method known as substitution. Plug in x from your second equation into your first equation

Answer 10

Do you understand how to do that?

Answer 11

not yet
looking at it
32+4?

Answer 12

Try this:


2(y+4)+2y=32
2y+8+2y=32
4y=24
y=6

Answer 13

So what I did there was I substituted x=y+4 into my first equation, 2x+2y=32

Answer 14

I see what you did but what is 4y=24 and y=6?

Answer 15

I combined 2y+2y (4y) and subtracted 8 from 32 (24)

Answer 16

Once you have 4y=24, you can divide both sides by 4 in order to solve for y

Answer 17

y=6?

Answer 18

Yeah. And now you can use y to solve for x. Remember that x=y+4

Answer 19

Length = 10
width = 6
would this be correct then?

Answer 20

Exactly

Answer 21

I have to go over this again from the top to double check our answers. Thank you very much. I want to make sure I understand.

Answer 22

I checke "best answer", hope you received a medal

Answer 23

No problem, if you have any questions just ask

Answer 24

ok