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Write an equation in slope-intercept form for the line shown.
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how do i find what goes where in y=mx+b
(2,-1)and (0,-4) y-(-1)=(-4+1)/(0-2) *(x-2)
1/-4??
\[y-(-1)=\frac{ (-4+1) }{ (0-2) }*(x-2)\] you are done
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what that is only m 1/-4 where is the rest?
the answers are y = 2/3 x + 2 y = 3/2 x - 4 y = 3x - 4 y = 2x - 1
i only havey=1/-4x+b
y-1= 3/2 * (x-2) y-1=3/2 x -3 y=3/2 x-2
sorry
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it's y=3/2 x -4
@EmmaH clear?
well how did you get 3/2 as m?
use formula (y2-y1)/(x2-x1)
hello?
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(-4+1)/(0-2)
oh ok
(:
and -4 how did you get that?
by rearranging the equations -3-1=-4
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thanks
(:
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