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Factor -x^3+3x-2
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-(x-1)(x+2)(x-1) now simplify this.
-(x-1)^2(x+2)
How do you get that so easily?
So you find what values you have to multiply to get 2
so like 1 times 2 is 2.
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there really isn't any other solution because that would be the only values that make 2.
Also these two values, 1 and 2 have to add up to the middle number.
Which is 3
ok... I'm still not sure how you find the three factors so easily. It looks like you're doing a trick similar when you have like x^2+bx+c.. finding two numbers that multiply to give c and adding them gives b... but I'm not sur ehow it's done with the ^3 at the front
Its the same, except it has 3 zeros
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two of them will be identical
o.o hm interesting I never saw this. Thanks
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