Question

graph f(x)=4x^2-8x+1 starting with the graph y=x^2

Answer 1

You can do that, but if I were you, I would re-write 4x^2 - 8x + 1 in vertex form first.

Answer 2

whats the vertex form?

Answer 3

f(x) = a(x-h)^2 + k, where (h,k) is the vertex. In this case:
f(x) = 4(x-1)^2 - 3

Answer 4

So now you can properly graph starting with y = x^2

Answer 5

where did the 3 come from?

Answer 6

@Hero

Answer 7

find the vertex of f(x) = 4x^2 - 8x + 1, then maybe you'll understand

Answer 8

i got it :) thank you @Hero

Answer 9

Are you done?

Answer 10

Did you start with y = x^2 and then get to f(x) = 4x^2 - 8x + 1