OpenStudy (anonymous):

Car with mass 940kg is moving at speed 48km/h. How much force do you need to stop it in 15m distance?

5 years ago
OpenStudy (ghazi):

first of all find the retardation \[(48)^2=2*a*D\] and \[a=\frac{ (48)^2 }{ 2*15 }=76.8m/s^2\] now F=m*a F=940*76.8 N @duck123 you are done

5 years ago
OpenStudy (ash2326):

@duck123 Did you understand?

5 years ago
OpenStudy (anonymous):

I'm trying to figure out where 2*a*d part is coming from

5 years ago
OpenStudy (ghazi):

\[V^2=U^2-2a*D\] V is final velocity which is zero and U is = 48 i have taken -a because it is retardation hope that helps

5 years ago
OpenStudy (anonymous):

oh, now i get it. thanks!

5 years ago
OpenStudy (ghazi):

:)

5 years ago
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