Question

find the slope of the function's graph at the given point, then find and equation for the line tangent to the graph
f(x)=x-2x^2 , (1,-1)

Answer 1

start by solving for the slope of the equation

Answer 2

okay

Answer 3

do you know how to do that?

Answer 4

i have to use this formula: y=mx+b?

Answer 5

or y2-y1/ x2-x1?

Answer 6

x= 1?

Answer 7

ok so now use the formula (y-y1)=m(x-x1)
where (x1,y1)=(1,-1)

Answer 8

slope=1?

Answer 9

no your slope will be m

Answer 10

yes sorry

Answer 11

using that equation i get y= mx-2

Answer 12

so y=x-2

Answer 13

okay,

Answer 14

now we need to find the inverse of the line

Answer 15

wait are you sure that you wrote the initial equation right because that is a hyperbola

Answer 16

let me check again

Answer 17

ok

Answer 18

it's y= mx-2

Answer 19

for the origional equation f(x)=x-2x^2

Answer 20

yes, its correct

Answer 21

ok well either way now we need to find the equation of a tangent line

Answer 22

how do I that?

Answer 23

1 sec g2g take a quiz b back in 10

Answer 24

okay,np

Answer 25

hmm after thinking about it i think i might have done this wrong

Answer 26

brb