Question

Can someone help me to solve this? square root of 2x^3y^3 times cube root of 4xy^2 Thank You!

Answer 1

Use the following rules
\[(xy)^{1/2} = x^{1/2}y^{1/2}\]
\[(x^2)^{1/2} = (x)^{2\frac{1}{2}} = (x)^{\frac{2}{1}\frac{1}{2}} = (x)^{\frac{(2)1}{2}}\]

Answer 2

where
\[(x)^{1/2} = \sqrt{x}\]
and
\[(x)^{1/3} = \sqrt[3]{x}\]

Answer 3

but the answer says: 2xy^2 6th root of 2x^5y

Answer 4

just to clarify in a case with a constant

\[(2x^2)^{1/2} = 2^{1/2}(x^2)^{1/2}\]

Answer 5

I'm showing yo how to simplify radicals

Answer 6

i know how to simplify, but my answer doesn't match with the book

Answer 7

what is your answer?

Answer 8

the answer is: 2xy^2 6th root of 2x^5y