Question

factor 2xy-4x+3y-6

Answer 1

I would group them first using parenthesis.

(2xy-4x)+(3y-6)

Answer 2

For the first parenthesis, factor out 2x.

2xy-4x=2x(y-2)

And for the second, factor out 3:

3y-6=3(y-2)

Answer 3

So our solution so far should look something like this...

(2xy-4x)+(3y-6) = 2x(y-2) + 3(y-2)

Answer 4

Finally, since we have a common factor of (y-2) that means we need to do one more factorization.

(2xy-4x)+(3y-6) = 2x(y-2) + 3(y-2) = (y-2)(2x+3)

Answer 5

Does that help?