Mathematics
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OpenStudy (anonymous):
Model the function rule y = -2x - 3 with a table of values?
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OpenStudy (anonymous):
plug in a few numbers for x and solve for y
OpenStudy (anonymous):
Still don't understand..
OpenStudy (anonymous):
What would I plug in and how do I solve for y? I'm really not good with Algebra.
OpenStudy (anonymous):
|dw:1351736026913:dw|
OpenStudy (anonymous):
start out buy drawing this for the sake of being lazy use small numbers for x
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OpenStudy (anonymous):
i like to anyways
OpenStudy (anonymous):
so far so good?
OpenStudy (anonymous):
Not really ha this sounds like babble to me. :/
OpenStudy (anonymous):
depending on your teacher he will want 3-5 x values
OpenStudy (anonymous):
lol ok. draw the graph on a piece of paper
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OpenStudy (anonymous):
and let me know when your done
OpenStudy (anonymous):
Like the one you've got ^?
OpenStudy (anonymous):
yes, but if you want to change the x values you can
OpenStudy (anonymous):
It doesn't matter as long as they're 3-5?
OpenStudy (anonymous):
pretty much
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OpenStudy (anonymous):
eh... I put
-3
0
2
OpenStudy (anonymous):
ok now what we need to do is plug these values into x
OpenStudy (anonymous):
lets start with -3
y = -2(-3) - 3
OpenStudy (anonymous):
so what would be the first step to solving this problem?
OpenStudy (anonymous):
Multiply -3 and -2?
then subtract 3 from that?
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OpenStudy (anonymous):
correct and what do you get?
OpenStudy (anonymous):
Y = -6 - 3
y = -9?
OpenStudy (anonymous):
|dw:1351736609957:dw|
OpenStudy (anonymous):
Oh two -'s make a positive...
OpenStudy (anonymous):
oops
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OpenStudy (anonymous):
you would get this because a negative times a negative = positive
OpenStudy (anonymous):
ok so you understand what we need to do now?
OpenStudy (anonymous):
Plug in the other two number.
y = 3
y = -7 ?
OpenStudy (anonymous):
yup you got it :)
OpenStudy (anonymous):
Sweet, thanks. and that's the answer?
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OpenStudy (anonymous):
when you put it into the chart ya|dw:1351736876704:dw|
OpenStudy (anonymous):
sorry 0 should =-3
OpenStudy (anonymous):
Oh alright. Thanks again.
OpenStudy (anonymous):
np glad to help