Question

Find the numerical value of cosh (ln5)

Answer 1

know the definition of cosh x ?

Answer 2

no?

Answer 3

yyes. e^x - e^-2 /2

Answer 4

e^-x *

Answer 5

now use ,the fact that \(\huge e^{ln a}=a\)

Answer 6

sorry it is + sign in between the e

Answer 7

yesm i know, now just put x=ln 5

Answer 8

i did, but i dont know what ot do for e^ -ln 5

Answer 9

where did that -ve sign go..

Answer 10

cuz it will become 5 + (-5) / 2 , then asnwer will be 0

Answer 11

for that , use log property
\(\large n log a=log a^n\)
n=-1 here

Answer 12

so -ln 5 will be ?

Answer 13

so it is loge^-ln4?

Answer 14

4 ?? how u got 4 ?

Answer 15

sorry 5, typo

Answer 16

original is e^-ln5

-ve is not the power of ln5, so how can u use log to bring it down?

Answer 17

\(\large n log a=log a^n \\ \large -log 5 =log (5^{-1})\)
got this ?

Answer 18

log = ln?

Answer 19

now use \(\large e^{ln (5^{-1})}=?\)
yes, its ln

Answer 20

5 + 1/5 ) /2

26/5 / 2= 13/5

Answer 21

thats correct, did u understand ?

Answer 22

yes i do, thanks!

Answer 23

welcome ^_^