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Mathematics 20 Online
OpenStudy (anonymous):

Simplify, help please!!??

OpenStudy (anonymous):

\[\LARGE 3\sqrt{128}\]

OpenStudy (anonymous):

Wait, do you mean 128 (divided) by 3? or the squareroot?

OpenStudy (anonymous):

33.94112

hartnn (hartnn):

its cube root, right ? \(\huge \sqrt[3]{128}\)

OpenStudy (anonymous):

\[\large A) 192\sqrt{2}\] \[\large B) 24\sqrt{2}\] \[\large C) 11\sqrt{2}\] \[\large D) 8\sqrt{2}\]

OpenStudy (anonymous):

@hartnn No, it's just \[\LARGE 3\sqrt{128}\]

hartnn (hartnn):

ok, can u simplify \(\huge \sqrt{128}=?\)

OpenStudy (anonymous):

c

OpenStudy (anonymous):

yes? i think?

OpenStudy (anonymous):

@hartnn

hartnn (hartnn):

write it as 128 = 64*2 and u know square root of 64 ?

OpenStudy (anonymous):

8, right?

hartnn (hartnn):

\(\text{yes so its }8\sqrt {2}\) and 3 was multiplied with it, so u get ?

OpenStudy (anonymous):

.... i don't know. do i multiply the 8 & 3 to make 24?

hartnn (hartnn):

yes!

OpenStudy (anonymous):

so it would be B?

hartnn (hartnn):

absolutely :)

OpenStudy (anonymous):

Thank you so much for explaining it :)

hartnn (hartnn):

welcome ^_^

OpenStudy (anonymous):

is c

OpenStudy (anonymous):

@fernando12 How did you get C?

hartnn (hartnn):

no, it isn't c.....

OpenStudy (anonymous):

in my book

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