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how do you do this equation using logs? 8^x = 10
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base of the exponent becomes base of the log, other two numbers are switched
take natural log on both sides ln8^x=ln10 xln8=ln10 x=ln10/ln8
\[\log_8 10= x\]
\[x=\log_{8}10=\frac{\log10}{\log 8}=\frac{1}{\log8}\]
Its easier with base 10 instead of e
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THANK YOU SO MUCH!!!
how do you do 2.4^x ≤ 20 using logs?
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