Question

inverse circular function.. i do not get it!
please give me full steps to complete question b) !!
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Answer 1

@amistre64 thank you!

Answer 2

the inverses of the trigs have to be restricted in order to give only 1 answer for any given input

the ranges are restricted by convention

Answer 3

for b. i believe the domain of sin^-1 is from 1 to -1 ; giving us outputs in the range pi/2 to -pi/2

Answer 4

sin(angle) = ratio

the inverse of a function just undoes it. It gets us back to the start again

inverse sin(ratio) = angle

Answer 5

the controling function as far as input goes in B is from the inverse sin function; for any value we place in it; it will give us a value from -pi/2 to pi/2

the cosine function takes this and plays with it. and spits out another ratio