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What is the vertical asymtote in f(x) = xe^-1/x^2
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what value makes the denominator 0
what is the denominator here
from the looks of your probelm its x^2
the function is x e^(-1/x^2)
oh, okay then take a look at the function e^(x), where does it have a vertial asymptote?
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1
oh actually no..0 i believe
actually it doesnt have one isnt it
thats right
so this function has no vertical asymtote?
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then does it not have horizontal asymtote too
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