3-x/11=12
lets guide her through this one so he can learn the steps
Okay.
we need to isolate x in the equation, so first step is to remove the 3 from the left side
wouldn't i have to add 3 on both sides in stead of subtracting?
but you have 3 on left side already, if you add 3 to both side you'll end up with 6, and you want the 3 to disappear, so you would subtract
i thought it would just cancel out?
If you add 3, you add 3 to another 3, which is not what we want. We want to "move" 3 to other side, so we have to remove 3 by subtract it.
3+3 = 6, 3-3 = 0
alright and then 3-12=9
so im stuck with x/11=12
*12-3 = 9 not other way around
Right. Now we need to deal with 11, do you know what to do?
then i would subtract 12 from 11 and 12?
so yes now you have x/11 = 12 how do we get ride of division, by doing the inverse of it right?
*rid
multiply
exactly, so we multiply by 11 to both sides to get rid of the division
so 12 would cancel out and 11 times 12 is 132
it's the 11 that's cancelled out from the right side, then remember we were left with 9 on the right side....so 9x11 = 99
sorry 11 would cancel out so I have 12 and x by itself
so would x=99?
No, we multiply both sides by 11, right? so now we have x = 12*11. 12*11=?
132
yep you got it, and no, we were left with 9 from subtracting 3 from both sides, so 9x11 = 99 x = 99
thank you so much! all the help means a lot!
never mind, i forgot that we subtracted 12 from 3 so x/11 = 9 so yeah, x = 99.
Glad we helped. (mostly Sheng, lol.)
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