Use synthetic division to find P(3) for P(x) = x4 – 6x3 – 4x2 – 6x – 2. a. 3 b. –137 c. 299 d. –47
are all your powers accounted for?
hmm, theres a simpler way; do you have to show your work?
Lemmme try one :)
give it a shot :)
ALRIGHTY! :)
no you dont have to show my work
im not sure how to use Use synthetic division here
\[3^3*3~<~3^3(-6)\]so the answer at least will be negative
the remainder of the synthetic is the same as the value of the poly
oh the remainder
so its 3?
3 is not a negative value .....
x4 – 6x3 – 4x2 – 6x – 2 0 <-- add this row ---------------------- 3 ) [R] <-- multiply this row
how you coming along with it Zofia?
Eh.. Not getting it lol
x4 – 6x3 – 4x2 – 6x – 2 0 <-- add this row ---------------------- 3 ) 1 [R] <-- multiply this row x4 – 6x3 – 4x2 – 6x – 2 0 3 <-- add this row ---------------------- 3 ) 1 [R] <-- multiply this row x4 – 6x3 – 4x2 – 6x – 2 0 3 <-- add this row ---------------------- 3 ) 1 -3 [R] <-- multiply this row x4 – 6x3 – 4x2 – 6x – 2 0 3 - 9 <-- add this row ---------------------- 3 ) 1 -3 [R] <-- multiply this row x4 – 6x3 – 4x2 – 6x – 2 0 3 - 9 <-- add this row ---------------------- 3 ) 1 -3 -13 [R] <-- multiply this row etc ...........................
Im still lost I reallly dont get synthetic division
then ask me questions about my method so i can see what your confusion might be
and, if you really dont get synthD, and you dont have to show your work; then just solve the equation for x=3
ok thank you.
good luck :) I have yet to come across a specific need for synthD; so far it just exists as a different method that might make life easier in some cases. So its good to have in your quiver.
@amistre64 Is it -47 im solving the problem right now
maybe .... x4 – 6x3 – 4x2 – 6x – 2 0 3 - 9 -39 -135 ------------------------ 3 ) 1 -3 -13 -45 my gut says in aint -47
So it would have to be -137 considering the values are negative right?
correct
B
Join our real-time social learning platform and learn together with your friends!