According tp the fundamental theorem of algebra, how many zeros does the polynomial below have? f(x)=x^3-10x^2+27x-12

Question

According tp the fundamental theorem of algebra, how many zeros does the polynomial below have?  f(x)=x^3-10x^2+27x-12

anonymous · Answer

Is the term (x + 2) a factor of the polynomial shown below?
f(x)=x^3-10x^2+27x-12

. _______________
-2)1 . -10 . 27 . -12
. ____-2__24_-102_
. . 1 . -12 . 51 . -114

anonymous · Answer

so the remainder is -114

anonymous · Answer

did u get it

anonymous · Answer

Fundamental theorem says that a polynomial function has a number of zeroes equal to the degree of the polynomial (the highest exponent on the variable).

anonymous · Answer

Understand, @pinkdollbaby1234 ?

anonymous · Answer

understood @pinkdollbaby1234

anonymous · Answer

thank you both , help me alot :) i think i got it now.