Question

Let the function "h" be defined by h(t)=2(t^3-3). When h(t)=-60, what is 2-3t?

Answer 1

-60=2(t^3-3).Solve for t.

Answer 2

t=3±3i√(3)/2

Answer 3

Hmm, how did you get that?
\(\large -60=2(t^3-3)\)
\(\large -30=t^3-3\)
\(\large -27=t^3\)
...

Answer 4

o, i used the quadratic formula

Answer 5

Ah, that won't work with a cubic. ;-)

Answer 6

Figure it out, @mitchelsewbaran ?

Answer 7

yeah, i got it, bro