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Mathematics 8 Online
OpenStudy (anonymous):

6x-y+3z=12

OpenStudy (anonymous):

6x-y+3z=12 x+3y-z=-6 3x+3y-4z=1

OpenStudy (anonymous):

@surdawi

OpenStudy (anonymous):

solve by elimination or what ever is easier

OpenStudy (anonymous):

easiest way eliminating the y

OpenStudy (anonymous):

6x-y+3z=12 x+3y-z=-6 and x+3y-z=-6 3x+3y-4z=1

OpenStudy (anonymous):

so i got 19x-8z=9 2x-3z=7

OpenStudy (anonymous):

12*3-6=?

OpenStudy (anonymous):

x-3x=? -z- -4z=? -6 -1=?

OpenStudy (anonymous):

36

OpenStudy (anonymous):

ugh i dont know what im doing right now!

OpenStudy (anonymous):

wait i the second one i multiply by -1 to get -x-3y-z=6

OpenStudy (anonymous):

then i elimated with the 3rd eqation

OpenStudy (anonymous):

or i can can times first equation by 3 and add the 3rd equation getting 21x+5z=40

OpenStudy (anonymous):

|dw:1351979056840:dw|

OpenStudy (anonymous):

making it the 5th equation

OpenStudy (anonymous):

x+3y-z=-6 3x+3y-4z=1 ------------- subtract and tell me what you got you have 3y in both equations

OpenStudy (anonymous):

2x+3x=5

OpenStudy (anonymous):

oops its 3z

OpenStudy (anonymous):

x-3x=? pay attention

OpenStudy (anonymous):

u there?

OpenStudy (anonymous):

sorry i had done it on paper! i got x=2 y=-3 z=-1

OpenStudy (anonymous):

answer is correct but u got the equation worn how did u do it right :P

OpenStudy (anonymous):

wrong*

OpenStudy (anonymous):

|dw:1351979942726:dw|

OpenStudy (anonymous):

hold on theres more!

OpenStudy (anonymous):

|dw:1351980131321:dw|

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