Mathematics
8 Online
OpenStudy (anonymous):
6x-y+3z=12
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OpenStudy (anonymous):
6x-y+3z=12
x+3y-z=-6
3x+3y-4z=1
OpenStudy (anonymous):
@surdawi
OpenStudy (anonymous):
solve by elimination or what ever is easier
OpenStudy (anonymous):
easiest way eliminating the y
OpenStudy (anonymous):
6x-y+3z=12
x+3y-z=-6
and
x+3y-z=-6
3x+3y-4z=1
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OpenStudy (anonymous):
so i got 19x-8z=9
2x-3z=7
OpenStudy (anonymous):
12*3-6=?
OpenStudy (anonymous):
x-3x=?
-z- -4z=?
-6 -1=?
OpenStudy (anonymous):
36
OpenStudy (anonymous):
ugh i dont know what im doing right now!
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OpenStudy (anonymous):
wait i the second one i multiply by -1 to get -x-3y-z=6
OpenStudy (anonymous):
then i elimated with the 3rd eqation
OpenStudy (anonymous):
or i can can times first equation by 3 and add the 3rd equation getting 21x+5z=40
OpenStudy (anonymous):
|dw:1351979056840:dw|
OpenStudy (anonymous):
making it the 5th equation
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OpenStudy (anonymous):
x+3y-z=-6
3x+3y-4z=1
------------- subtract and tell me what you got you have 3y in both equations
OpenStudy (anonymous):
2x+3x=5
OpenStudy (anonymous):
oops its 3z
OpenStudy (anonymous):
x-3x=? pay attention
OpenStudy (anonymous):
u there?
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OpenStudy (anonymous):
sorry i had done it on paper! i got x=2 y=-3 z=-1
OpenStudy (anonymous):
answer is correct but u got the equation worn how did u do it right :P
OpenStudy (anonymous):
wrong*
OpenStudy (anonymous):
|dw:1351979942726:dw|
OpenStudy (anonymous):
hold on theres more!
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OpenStudy (anonymous):
|dw:1351980131321:dw|