400 x^2+680+289
i believe it is to factor the expression
Can anyone tell me wat the answer is? You have to factor it..... its a perfect square trinomial!
and the expression should be corrected to \[400x^2+680x+289\]
Found some details here http://openstudy.com/updates/5095a758e4b0d0275a3ca9e2
yahhh it is
two birds in one shot for @CliffSedge . haha
i don't get it plzzz someone help me!!!!! :(
Let's start with an easier example first so you can see what's going on. Take \((2x+3)^2\) = \((2x+3)(2x+3)\) = \(4x^2+12x+9\), yes?
4 = 2^2 9 = 3^2, and 12 = 2×2×3
Knowing that \((a+b)^2\) = \(a^2+2ab+b^2\), Once you find a and b, you have the factored form, by putting them in \((a+b)(a+b)\)
Since you know that 400 = 20^2 and 289 = 17^2, you're done.
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