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Mathematics 15 Online
OpenStudy (anonymous):

400 x^2+680+289

OpenStudy (sirm3d):

i believe it is to factor the expression

OpenStudy (anonymous):

Can anyone tell me wat the answer is? You have to factor it..... its a perfect square trinomial!

OpenStudy (sirm3d):

and the expression should be corrected to \[400x^2+680x+289\]

OpenStudy (anonymous):

Found some details here http://openstudy.com/updates/5095a758e4b0d0275a3ca9e2

OpenStudy (anonymous):

yahhh it is

OpenStudy (sirm3d):

two birds in one shot for @CliffSedge . haha

OpenStudy (anonymous):

i don't get it plzzz someone help me!!!!! :(

OpenStudy (anonymous):

Let's start with an easier example first so you can see what's going on. Take \((2x+3)^2\) = \((2x+3)(2x+3)\) = \(4x^2+12x+9\), yes?

OpenStudy (anonymous):

4 = 2^2 9 = 3^2, and 12 = 2×2×3

OpenStudy (anonymous):

Knowing that \((a+b)^2\) = \(a^2+2ab+b^2\), Once you find a and b, you have the factored form, by putting them in \((a+b)(a+b)\)

OpenStudy (anonymous):

Since you know that 400 = 20^2 and 289 = 17^2, you're done.

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