Question

Solve:
27x^2-7x=0

Answer 1

just factor it and solve for x

Answer 2

(3n+1)(9n-7) ??

Answer 3

\[\boxed{ax^2+bx+c=0}\rightarrow\large{{x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}}}\]

Answer 4

Huh?

Answer 5

thats the quadratic equation, also another method of solving for the roots

you factored it incorrectly

now looking at the expression 27x^2-7x
we look for any common variables or multiplies that they share

notice they both have x in it, so we can factor it out using the distributive property

this now gives us

x(27x-7)

can you solve the problem now?

Answer 6

20x

Answer 7

minus7 from both sides?

Answer 8

no....

the equation after you factor the left side would be

x*(27x-7)=0

now in order to get zero through multiplication, that means one of the multiplies needs to be zero

this means
either x= 0 or 27x-7=0

now solve for x

Answer 9

if x=0 then 27x^2 - 7x= 0

Answer 10

no...
there are 2 different answers for x

Answer 11

x is 0 and x is ___ looks like a negative number?

Answer 12

no its positive

SOLVE FOR X
27x-7=0

Answer 13

27x=7 then divide both sides by 7 right?

Answer 14

27...

Answer 15

oops

Answer 16

7/27

Answer 17

YES..

x= 0 AND x=7/27

Answer 18

Phew....Thank you!