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Mathematics 18 Online
OpenStudy (laddiusmaximus):

find dy/dx by implicit differentation x^2+xy-y^2=4

OpenStudy (anonymous):

(x^2) ' + (xy)' -(y^2)' =0

OpenStudy (anonymous):

(xy) ' product rule: x' *y + x *y' x' is just 1, so y+ x* y '

OpenStudy (anonymous):

try (y^2)' ... use the chain rule..

OpenStudy (laddiusmaximus):

yeah its 2y*y'

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

2x + y+ x* y ' +2y* y' =0

OpenStudy (anonymous):

solve for y ' algebraically...

OpenStudy (laddiusmaximus):

factor out y'

OpenStudy (anonymous):

yeah, move the 2x and the y to the other side and then factor y ' out of the remaining terms..

OpenStudy (laddiusmaximus):

so it would be -2x-y in the numerator?

OpenStudy (laddiusmaximus):

is -2x-y the same as 2y+y?

OpenStudy (anonymous):

yes it's the numerator

OpenStudy (anonymous):

first find value of first derivative and arrange equation take dy/dx next to one another take commondy/dx and take the other value to other side

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