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\[\sqrt{2x -3} - \sqrt{x+7} = 4\]
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square both sides.
what u get ?
Take one sqrt term to right that would be easy
i doubt that... just the same thing....squaring twice will be necessary
wait 1 min plz
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i dont understand the 3rd setp
its squared both sides in third step
\((x-26)^2=8^2\sqrt{x+7}^2\)
for left side use \((x-a)^2=x^2-2ax+a^2\)
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okk
any more doubts ?
yes i got it:)
nop
good...
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i have doubt one question
which >
this one
the question is: \[x=2y\] \[\sqrt{x+y} - \sqrt{x-y} = 2\]
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which step ?
All setps
first you replace x by 2y then square both sides.
what u get ?
isn't it x=2y+1 ??
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is system equation
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