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\[ \int \frac{x}{x^2+1}dx \]
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this (almost) looks like u^-1 du
This smells of parts, but I'm having trouble with \[\int\limits \frac{1}{x^2+1}dx\]
that is arctangent
Although that might not help
can you enlighten us with the problem?
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Do a substitution \(u=x^2, du=2xdx\)
\[0.5 \ln(u+1)\]
@sirm3d It's halfway through the DE of my last question
Yes. Now make the inverse substitution.
post a link @henpen
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hmm, can we try reduction of order with \[y=v(ix)\]
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