9) The width of a rectangle is x inches long. The length of that rectangle is 6 inches less than
twice the width. If the perimeter measures 48 inches, what is the measure of the length
and width of the rectangle. Show all the work and the algebra you used to solve this problem.

Question

9)	The width of a rectangle is x inches long. The length of that rectangle is 6 inches less than 
twice the width.  If the perimeter measures 48 inches, what is the measure of the length
and width of the rectangle.  Show all the work and the algebra you used to solve this problem.

anonymous · Answer

width = x 
length = 2*x-5 
perimeter = 2*(x + 2x-5) 

According to question.. 

 
2*(x+2x-5) = 26 
=> 6x -10 =26 
=> x = 36/6 = 6 
width = 6 inches
length = 7 inches.

anonymous · Answer

since they are two different numbers don't i have to switch them?

anonymous · Answer

width = x 
length = 2*x-6
perimeter = 2*(x + 2x-6) 

According to question.. 

 
2*(x+2x-6) = 48
=> 6x -12 =48
=> x = 10
width = 10
length =14

anonymous · Answer

nope everythink is wrong @pkjha3105

anonymous · Answer

those problmes are easy and peasy

anonymous · Answer

thts y u hd mistakn to solve it..lol

anonymous · Answer

no i dont have any mistake man u are mistake the whole problem i have IM

anonymous · Answer

whre is the mistke?