Question

9) The width of a rectangle is x inches long. The length of that rectangle is 6 inches less than
twice the width. If the perimeter measures 48 inches, what is the measure of the length
and width of the rectangle. Show all the work and the algebra you used to solve this problem.

Answer 1

width = x
length = 2*x-5
perimeter = 2*(x + 2x-5)

According to question..


2*(x+2x-5) = 26
=> 6x -10 =26
=> x = 36/6 = 6
width = 6 inches
length = 7 inches.

Answer 2

since they are two different numbers don't i have to switch them?

Answer 3

width = x
length = 2*x-6
perimeter = 2*(x + 2x-6)

According to question..


2*(x+2x-6) = 48
=> 6x -12 =48
=> x = 10
width = 10
length =14

Answer 4

nope everythink is wrong @pkjha3105

Answer 5

those problmes are easy and peasy

Answer 6

thts y u hd mistakn to solve it..lol

Answer 7

no i dont have any mistake man u are mistake the whole problem i have IM

Answer 8

whre is the mistke?