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Decompose this rational expression into partial fractions. -6x/(x-6)(x+3)
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what have u tried so far?
-3/(x-6)+-1/(x+3)
\[\large \frac{-6x}{(x-6)(x+3)}\]
so how did u get to that (your answer there)?
it was the mutiple choise answer like the textbook iam using for my online class is confusing
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Just some help: What you wanna do is something like this,\[\frac{-6x}{(x-6)(x+3)} = \frac{A}{(x-6)}+\frac{B}{(x+3)}\]
x-2/x+4=x=6/x-4
and then solve for A and B
ah thanks
lemme know if you still have problems
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for this one qustion x-2/x+4=x-6/x-4 i got x=8
question
i get x = 8 as well
it fits in with the equations
x-6/x<-1
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x≤ -3 or x≥0
right
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