Use the addition and subtraction formulas to find the exact value of the expression. Tan 165 degrees.
Hmmm I think they probably want you to break it up like this. \[\large \tan(165^o)=\tan(135^o+30^o)\]
what would you do next?
\[\large \tan (a+b)=\frac{ \tan a + \tan b }{ 1- \tan a \tan b }\] Hmmm we can use the sum formula for tangent. 135 and 30 both correspond to special angles for the tangent, so it will break down pretty nicely.
\[\large \tan(135+30)=\frac{ \tan135+\tan30 }{ 1-\tan135 * \tan30 }\] Understand the setup? :D
well i tried it like this and it doesnt work out, or idk what to do next
sorry its backwards! :o
lolol backwards XD
haah idk how to fix it :/
Oh i see, you broke up the numbers differently. Looks like you were able to break it up so they're still special angles though, so that's good :) hmm
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