Question

Suppose y(t)=9e^(−5t) is a solution of the initial value problem y′+ky=0, y(0)=y0. What are the constants k and y0?

Answer 1

plug y(t)=9e^(−5t) into the differential equation and what do you get?

Answer 2

y′+k9e^(−5t)=0 ??

Answer 3

what is y' ?

Answer 4

dy/dt right?

Answer 5

yes, and what is that for the given y ?

Answer 6

-45e^(−5t) ?

Answer 7

yes, plug that into the equation as well and solve for k

Answer 8

45/9 thank you

Answer 9

welcome