(3,-6); 7x+2y=9 write the equation of the line containing the given point and the perpendicular to the given line.
what's the slope of 7x + 2y = 9?
well it wants the answer in point slope form.
ok, but you have to find the slope of the first line first before you can do anything else
thats all my paper has im stuck in this question. unless the slope would be 3,-6 thats my guess.
wait unless its y+6= 2/7 (x-3)
that's right..
that's your answer lol. good job
na no way really.
serious, bro. idk how you got it so fast, but BAM. there ye go
lol but i dont even know how to start with the first step.
well i wanna know to get the answer.
would be like y=mx+b type thing.
ok, so you change 7x + 2y = 9 into slope-intercept form. 7x + 2y = 9 2y = -7x + 9 y = -7/2x + 9/2
and the slope in y = -7/2x + 9/2 is -7/2
so if you want the slope of the line that's perpendicular to this, you find the negative reciprocal of -7/2, which is 2/7
point-slope form is: y - y1 = m(x - x1) our y1 is -6, x1 is 3, and m is 2/7. so... y + 6 = 2/7(x - 3)
wow dude the answer was in my notes but i was like no way thats why i wanted to know the steps to the answer thx.
no problem :) i hope that made sense
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