A trough is 12 feet long and 3 feet across the top. Its end are isolates triangles with altitudes of 3 feet. If water is being pumped into the trough at 2 cubic feet per min, how fast is the water level rising when the water is 1 foot deep?
Is this what question means?|dw:1352122545575:dw|
anybody helps me, please.
Seems like thats the question, yes. And to calculate it you got 2 cubic feet per min. So you have calculate total cubic feet. And find out how many cubic meters at under water at 1 feet hight, then you know how much you have left, and can calculate speed from there on.
V = 1/2 blh where b represnts base, h is height, and l is length so the volume of this shape is 54 ft³, right? NOw I have to derivative volume and heigh, right?
while rising, height and base changes so three unknown variables... right?
54ft³ is correct. on the rest Length stays the same, height is given (1). base is unknown. But the triangles and the same proportions, just calculate them to get the new base.
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