Question

Write the equation in logarithmic form.
2^5 = 32

A. log32 = 5 • 2

B. log232 = 5

C. log32 = 5

D. log532 = 2

Answer 1

@jim_thompson5910

Answer 2

Hint:

\[\Large b^x = y\]

converts to

\[\Large \log_{b}(y) = x\]

Answer 3

that confused me a bit

Answer 4

in your case, b is 2, x is 5 and y is 32

Answer 5

do the proper replacements

Answer 6

log32 = 5 times 2??

Answer 7

no

Answer 8

o haha im so confused

Answer 9

ex:

\[\Large 3^4 = 81\]

converts to

\[\Large \log_{3}(81) = 4\]

Answer 10

how do i put that 3 in my calculator

Answer 11

\(\Large 3^4\) = 3 ^ 4

Answer 12

and there's no need to use your calculator for this problem

Answer 13

o ok

Answer 14

so what am i doing lol

Answer 15

you're just going from something like

\[\Large 3^4 = 81\]

to

\[\Large \log_{3}(81) = 4\]

Answer 16

except I used different numbers

Answer 17

im 100% LOST

Answer 18

\[\Large 3^4 = 81\] is in exponential form

\[\Large \log_{3}(81) = 4\] is equivalent, but its in logarithmic form

Answer 19

that's all you're doing: converting from exponential form to logarithmic form

Answer 20

my calculator wont let me do it error and idk how to do it without it

Answer 21

you don't need a calculator, all you're doing is rearranging the numbers

Answer 22

the base becomes the base of the log

the exponent goes on the right side

the number that was on the left side goes inside the log

Answer 23

becomes