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Mathematics 5 Online
OpenStudy (anonymous):

Solve for x. State any restrictions on the variables. a (bx+2)=cx-12

OpenStudy (anonymous):

@sirm3d

OpenStudy (anonymous):

@zepdrix

OpenStudy (anonymous):

does this have no restrictions

OpenStudy (anonymous):

it's not written as an equation... there is no equals sign. Is that how it shows on your site, or did something not paste correctly?

OpenStudy (anonymous):

i fixed it lol sorry

OpenStudy (anonymous):

a (bx+2)=cx-12 I would start by multiplying out the left side: abx + 2a = cx - 12 Then put all the x's on the left and the numbers on the right: abx - cx = -2a - 12 Then factor out the x on the left: x(ab - c) = -2a - 12

OpenStudy (anonymous):

Finally, you could divide both sides by ab - c to solve for x: x = (-2a - 12) / (ab - c) There are restrictions... ab - c can't be equal to 0, since that would make the denominator equal 0... not allowed :)

OpenStudy (anonymous):

No magic on this one... it was just simplifying and solving, then remembering that you can't divide by zero.

OpenStudy (anonymous):

you could simplify it further though... could factor out a negative 2... x = -2(a + 6) / (ab - c)

OpenStudy (anonymous):

that rules out one of my answers then

OpenStudy (anonymous):

some of your answers were based in magic?

OpenStudy (anonymous):

huh

OpenStudy (anonymous):

forget it, dumb joke. Do your answers not include that last simplified expression for x?

OpenStudy (anonymous):

|dw:1352174527378:dw|

OpenStudy (anonymous):

this is what i got not sure if its right

OpenStudy (anonymous):

that looks right... just different order on top than what I had... but same thing.

OpenStudy (sirm3d):

i agree with @JakeV8 .

OpenStudy (anonymous):

|dw:1352174695388:dw|

OpenStudy (anonymous):

|dw:1352174797511:dw|

OpenStudy (anonymous):

so i was right

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