Question

can anyone help me on solution triangle,not a right angle triangle

Answer 1

if side a and b is given..angle A is given..solves c,angle B and angle C

Answer 2

use the law of sines
do you have specific numbers?

Answer 3

no..but how i should do to get c?

Answer 4

\[\frac{\sin(A)}{a}=\frac{\sin(B)}{b}\]

Answer 5

without using specific value..can u derived formulae to get c and angle C

Answer 6

once you have angle B you know angle C since they add to 180

Answer 7

then you can use \(\frac{c}{\sin(C)}=\frac{a}{\sin(A)}\) to find \(c\)

Answer 8

o i c..thanks..

Answer 9

yw

Answer 10

c\[c^{2} = a ^{2}+b ^{2}-2abcosC\]

Answer 11

then i will get c..thanks

Answer 12

you can use that as well, but it is generally easier to use the law of sines than the law of cosines

Answer 13

you get in one step
\[c=\frac{a\sin(C)}{\sin(A)}\]

Answer 14

o i c...ok