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Can someone help me with this problem? My problem is attached
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I believe its a.
\[m=\frac{y-y _{1}}{x-x _{1}}=\frac{4-0}{-6-2}=-\frac{1}{2}\] Therefore the slope is -(1/2). Do you understand so far?
Yes it is a ..... equation...is \[Y-Y_{1} = M(X-X_{1})\] Where M is slope.. M =\[\frac{ Y_{2}-Y_{1} }{X_{2}-X_{1} }\] there fore M=\[\frac{ 0-4 }{2--6 }=\frac{ -4 }{2+6 }=\frac{ -4 }{8}=\frac{ -1 }{2 }\] and substituting the point \[(X _{1},Y _{1})\] in the standard equation we get answer A
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