Question

What are the real or imaginary solutions of the polynomial equation?

Answer 1

put x^4=t^2 and try to solve

Answer 2

i still don't understand..

Answer 3

substitute x^4 = t^2
you get t^2 - 41t + 400 = 0
can u solve this quadratic equation

Answer 4

i can try i just dont understand algebra at all

Answer 5

just solve for t then put x^2 = t. u get x.
u got it ?
don't worry keep on practising and you will start loving the subject

Answer 6

BTW, there are 4 solutions and all of them are real. No imaginary zeros

Answer 7

thanks you guys i will try to figure it out!

Answer 8

try factoring
\[t^2-41t+400=0\] it actually factors

Answer 9

and a hint is that the two numbers whose product is 400 are both perfect squares

Answer 10

thank you very much for your help!

Answer 11

did you get \((t-16)(t-25)=0\)? if so then you go to \(x^2-16=0,x^2-25=0\) and solve both of those for \(x\)

Answer 12

oh alrighty. thanks :)