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A cylindrical tank with radius 5m is being filled with water at a rate of 3m^3/min. How fast is the height of the water increasing? I got (3/25pi) -10h = dh/dt but the answer is just 3/25pi why?
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@luclucluc do you want to show your working?
dv/dt= pi(2rh + dh/dtr^2) isolate dh/dt=(dv/dt/pi)-2rh then I subbed in dv/dt and r and got my answer
You need to use the formula for Volume !
isn't it v=(pi)r^2h? for a cylinder?
V = π r² h At r = 5 -> V = 25π h -> dV/ dt = 25π dh/ dt => dh/dt = 3 / (25π )
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Oh I see thank you so much !
Don't overdo it :)
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