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Can someone help me with this question: Create a polynomial of the lowest degree, with rational coefficents, with the given zeors (leave you answer in factored form, do NOT simply: a) 2 with a multiplicy of 2 and 5i
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does this look like : \[(x-2)^{2}-5i\]
? wait 5i needs an x
\[is \it: (x-2)^{2}(x+5i)\]
that wouldn't work because 5i isnt a rational coefficient...if you have one complex solution, you also must have its conjugate (im pretty sure) so you have to find a factor that has +/- 5i in it
oh thats right i forget the conjugate
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so i need to [x-1+5i][x-1-5i] do i need to factor this first
?
why dont you just use the factor x^2+25
oh i see, ok I got it thank you!!!
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