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Mathematics 19 Online
OpenStudy (rmrjr22):

Find the Maximum possible product of three positive numbers whose sum is 120.

OpenStudy (anonymous):

is the value of the product 64000

OpenStudy (rmrjr22):

how?

OpenStudy (anonymous):

for completely solving u can use the Langranges method of multiplier..

OpenStudy (rmrjr22):

would you need a constraint?

ganeshie8 (ganeshie8):

also in simple terms, a cube volume is the greatest for a given sum of dimensions, coz a square area is greatest for a given perimeter

OpenStudy (anonymous):

@ganeshie8 yup agree

OpenStudy (rmrjr22):

\[\sqrt[3]{120?}\]

OpenStudy (anonymous):

lagrange's multiplier is little bit complicated since you would have to build a constraint you can assume the numbers to be x, x+1 and x+2 and then use derivative to find the the maximum value

OpenStudy (rmrjr22):

then what can i use as an equation? constraint?

OpenStudy (anonymous):

|dw:1352265753890:dw|

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