Find the Maximum possible product of three positive numbers whose sum is 120.

Question

anonymous · Answer

is the value of the product 64000

rmrjr22 · Answer

how?

anonymous · Answer

for completely solving u can use the Langranges method of multiplier..

rmrjr22 · Answer

would you need a constraint?

ganeshie8 · Answer

also in simple terms, a cube volume is the greatest for a given sum of dimensions, coz a square area is greatest for a given perimeter

anonymous · Answer

@ganeshie8 yup agree

rmrjr22 · Answer

$$\sqrt[3]{120?}$$

anonymous · Answer

lagrange's multiplier is little bit complicated since you would have to build a constraint you can assume the numbers to be x, x+1 and x+2 and then use derivative to find the the maximum value

rmrjr22 · Answer

then what can i use as an equation?
constraint?

anonymous · Answer

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