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Find the Maximum possible product of three positive numbers whose sum is 120.
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is the value of the product 64000
how?
for completely solving u can use the Langranges method of multiplier..
would you need a constraint?
also in simple terms, a cube volume is the greatest for a given sum of dimensions, coz a square area is greatest for a given perimeter
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@ganeshie8 yup agree
\[\sqrt[3]{120?}\]
lagrange's multiplier is little bit complicated since you would have to build a constraint you can assume the numbers to be x, x+1 and x+2 and then use derivative to find the the maximum value
then what can i use as an equation? constraint?
|dw:1352265753890:dw|
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