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determine if existent the limit: lim -->0 sinx-x/x^3
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can you put parenthesis to make the problem a little more clear?
is it \[\lim_{x \rightarrow 0} \frac{ sinx-x }{ x^{3} }\]
Yes that is the exact question.. @Eda2012
Can you use :'hopital's rule?
L'hopital's rule*
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Yes, we can use Hopital rule!
that makes it so much easier @Dido525 thanks for thinking of that
Okay then! Take the derivative of the top and bottom terms :) . But before that check if the limit is 0/0 or infinity/ infinity.
Haha. I always ask ^_^ .
Yeah the limit is 0/0 if you directly sub in.
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I need to show step by step to the professor :( lol... can anybody do that for me.. sorry guys
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