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OpenStudy (anonymous):
1/2a^2 - 1/4a For a=4
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OpenStudy (lgbasallote):
substitute a with 4....where are you confused tehre?
OpenStudy (anonymous):
1/2(4)^2 - 1/4(4)
1/2 (16) - 1/4(4)
16/2- 4/4 ???
OpenStudy (lgbasallote):
that depends... is the question \[\frac 12 a^2 - \frac 14a\]or\[\frac 1{2a^2} - \frac 1{4a}\]
OpenStudy (anonymous):
its
1/2a2 - 1/4a
OpenStudy (lgbasallote):
?
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OpenStudy (anonymous):
a^2
OpenStudy (lgbasallote):
a^2 = \(a^2\)
OpenStudy (anonymous):
I am working on polynomials. The question says to "Evaluate the expression"
1/2a^2 - 1/4a For a= 4
OpenStudy (lgbasallote):
and i am asking you how the question looks like...
OpenStudy (anonymous):
How do you get your equation to look like a real exponent on here?
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OpenStudy (lgbasallote):
is the a in the denominator or not?
OpenStudy (lgbasallote):
is it \[\huge \frac 12 a^2 - \frac 14a\]
or \[\huge \frac 1{2a^2} - \frac 1{4a}\]
OpenStudy (anonymous):
no, it is to the side of the of the fraction
OpenStudy (lgbasallote):
then you're right
OpenStudy (anonymous):
Got it.... thank you- but seriously. how did you type out the equation like that on the computer
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OpenStudy (lgbasallote):
do you see that box that says \[\huge \boxed{\sum \; \rm{Equation}}\]
OpenStudy (lgbasallote):
below the comment box
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
oh.. cool.. thank you
OpenStudy (lgbasallote):
welcome
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