Question

8/9-a^2 divided by 4a^2-4a-24/a^2-6a+9=

Answer 1

@Hero i need help

Answer 2

@KatieMO

Answer 3

@amistre64 (Moderator)

Answer 4

Simplify both parts first\[\frac{ 4a^2-4a-24 }{ a^2-6a+9 }=\frac{ 4(a^2-a-6) }{ a^2-6a+9 }=\frac{ 4(a-3)(a+2) }{ (a-3)(a-3) }=\frac{ 4(a+2) }{ (a-3) }\]\[\frac{ 8 }{ (9-a^2) }=\frac{ 8 }{ (3+a)(3-a) }\]So now we have\[\frac{ 8 }{ (3+a)(3-a) }\div\frac{ 4(a+2) }{ (a-3) }=\frac{ 8 }{ (3+a)(3-a) }\times\frac{ (a-3) }{ 4(a+2) }=\frac{ 8 (a-3)}{ (3+a)(3-a)4(a+2)}\]I think distributing will be the last step. I'll let you do that.\[\frac{ 2 (a-3)}{ (3+a)(3-a)(a+2)}\]

Answer 5

(a+2) was cut off