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Perform the indicated operation. I will attach a picture below ^-^
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First, change from dividing to multiplying: \[\frac{8}{9-a^2} \div \frac{4a^2 - 4a - 24}{a^2-6a+9} = \frac{8}{9-a^2} \times \frac{a^2-6a+9}{4a^2 - 4a - 24}\]
Next, factor: \[\frac{8}{-(a-3)(a+3)} \times \frac{(a-3)^2}{4(a-3)(a+2)}\]
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Yes ^-^ Thank you so much!
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No problem, glad I could help you, since I was homeschooled as well.
Haha yeah. This is my first year of home schooling. I was surprised on how hard the work was ^-^
Very true, hope you keep at it! =)
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