Question

helppp plzzzz


-5k^2+10k-13=-8


a,0;two imaginary solution
b,0;0ne real solution
c,c,200;two real solution
d,0;two real solution

Answer 1

start with \(5k^2-10k+5=0\) then maybe divide by 5 and get
\[k^2-2k+1=0\]

Answer 2

this is a perfect square, namely \((k-1)^2=0\) and so there is only one real solution

Answer 3

thank you @satellite73

Answer 4

yw